Minus' Solution to

Hickory, Dickory, Dock
Posted July 15 - 21, 1996

Each mouse was moving from one number to the next every hour. After 6 hours, both would be at the bottom of the clock when it was 6 a.m.

Your Solutions

George Schmaltz [gschmaltz@ghs03.ghs.gmcs.k12.nm.us] gave Minus exactly what he was looking for:

Rodentia would run around the clock moving at a rate of 1 position (each hour on the time clock) in 1 hour. Micki would be moving at the same rate. Therefore, they would meet at the 6 o'clock position or at 6:00 a.m. They would meet again at the twelve, then at the six, then at the twelve, etc.

Joseph Samuel Stewart [joest@flash.net] also submitted a correct solution:
It only stands to reason that if Micki and Rodentia took three hours to get to the three and continued at their steady pace, they would come together at the 6 in three hours and it would be 6:00 a.m.

Minus wanted us to mention Gurpreet Saran [gsaran@direct.ca] and Michelle [MichelleH@sisna.com] for sending in their answers of 6:00 am. 

Kudos to everyone who sent in
solutions to Minus, the math shark.
We're going to have to put him on
a diet at this rate!